2v^2-17v+35=0

Solution for 2v^2-17v+35=0 equation:

2v^2-17v+35=0

a = 2; b = -17; c = +35;
Δ = b2-4ac
Δ = -172-4·2·35
Δ = 9
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$v_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$v_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{9}=3$
$v_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-17)-3}{2*2}=\frac{14}{4}
=3+1/2
$
$v_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-17)+3}{2*2}=\frac{20}{4}
=5
$